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0.25x^2-11x=800
We move all terms to the left:
0.25x^2-11x-(800)=0
a = 0.25; b = -11; c = -800;
Δ = b2-4ac
Δ = -112-4·0.25·(-800)
Δ = 921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{921}}{2*0.25}=\frac{11-\sqrt{921}}{0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{921}}{2*0.25}=\frac{11+\sqrt{921}}{0.5} $
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